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1000=5500-5x^2
We move all terms to the left:
1000-(5500-5x^2)=0
We get rid of parentheses
5x^2-5500+1000=0
We add all the numbers together, and all the variables
5x^2-4500=0
a = 5; b = 0; c = -4500;
Δ = b2-4ac
Δ = 02-4·5·(-4500)
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{90000}=300$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-300}{2*5}=\frac{-300}{10} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+300}{2*5}=\frac{300}{10} =30 $
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